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motion09

Joined: 19 Sep 2010
Posts: 4

 Posted: Wed May 11, 2011 12:01 am    Post subject: Heat Energy A 200g piece of ice at -10 deg. C is placed in 200 g of water at 50 deg. C. After a few minutes the ice-water mixture reaches thermal equilibrium. How much water is there in the mixture now? I'm not sure if I have to use the formula for latent heat of vapourization or not. Thanks!
hepcj

Joined: 23 Jun 2007
Posts: 125

 Posted: Wed May 11, 2011 11:37 pm    Post subject: I would use the latent heat of fusion for ice. Latent heat of vaporisation is for liquid changing into a gas. The only way that the ice-water can be equilibrium will be when they are both at 0 deg C. The heat lost by the water will be Q_lost=m_water * C_water * 50 while heat gained by the ice will be because of the latent heat to reach 0 deg C. Q_gain = m_ice * L_ice * 10 The energy lost by water = energy gained by the ice . Solve for the mass of ice. The mass of water in kg will be 0.2 + (0.2 - mass of ice).
motion09

Joined: 19 Sep 2010
Posts: 4

 Posted: Sat May 14, 2011 2:40 pm    Post subject: Thanks!
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